Solution to Day 3 of 7 Days of JS

I wrote first the solution using a while loop:

function sign(array) \{
  let count = array.length;
  let i = 0, positives = 0, negatives = 0, zeros = 0;
  while (i < count) \{
    if (array[i] === 0) \{
      zeros += 1;
    } if (array[i] > 0)\{
      positives += 1;
    } if (array[i] < 0)\{
      negatives += 1;
    }
    i++;
  }
  return \{zeros, positives, negatives};
}

console.log(sign([-3,0,6,2]))

And it works! Then, I wrote the same but with a for loop:

function sign(array) \{
  let count = array.length;
  let positives = 0, negatives = 0, zeros = 0;
  for (let i = 0; i < count; i++) \{
    if (array[i] === 0) \{
      zeros += 1;
    } if (array[i] > 0)\{
      positives += 1;
    } if (array[i] < 0)\{
      negatives += 1;
    }
  }
  return \{zeros, positives, negatives};
}

console.log(sign([3,-1,0,-2]))

You may want to write this function using the Math.sign() method. You can read about it here.

Do you have a different solution? Share it in the comments!